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Old Feb 3rd, 2013, 09:46 PM   #16
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Re: Barthel 2013 = Kerber 2012

You are off the mark on half the events And a third vs. first round in a Grand Slam is quite a significant difference
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Old Feb 3rd, 2013, 10:07 PM   #17
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Re: Barthel 2013 = Kerber 2012

Quote:
Originally Posted by VeeJJ View Post
Not yet. Mona is more talented IMO she just has to hone her skills and she can be a real threat.
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Old Feb 3rd, 2013, 10:08 PM   #18
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Re: Barthel 2013 = Kerber 2012

Quote:
Originally Posted by Jane Lane View Post
She needs to actually, you know, win matches at slams first. 4 R1 losses in a row.
This
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Old Feb 3rd, 2013, 10:15 PM   #19
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Re: Barthel 2013 = Kerber 2012

Quote:
Originally Posted by SAISAI-GOAT View Post

feel as Barthel is ready to enter the SEWTA Top 10 in 2013
is the wta even sponsored by sony anymore?
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Old Feb 3rd, 2013, 10:17 PM   #20
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Re: Barthel 2013 = Kerber 2012

Quote:
Originally Posted by Jane Lane View Post
She needs to actually, you know, win matches at slams first. 4 R1 losses in a row.


This.
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Old Feb 3rd, 2013, 10:20 PM   #21
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Re: Barthel 2013 = Kerber 2012

The most glaring difference in comparison that truly tells is that entering the 2012 AO Kerber was a Semi Finalist at the previous USO losing to the eventual champion in three sets. In contrast Barthel entering the 2013 AO was a 1st round loser in the previous USO.
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Old Feb 3rd, 2013, 10:26 PM   #22
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Re: Barthel 2013 = Kerber 2012

She was injured for half of the season last year, wasn't she?
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Old Feb 3rd, 2013, 10:30 PM   #23
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Re: Barthel 2013 = Kerber 2012

Quote:
Originally Posted by Leo St View Post
is the wta even sponsored by sony anymore?
No.
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Old Feb 4th, 2013, 02:10 PM   #24
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Re: Barthel 2013 = Kerber 2012

Barthel's game (smooth big hitting, quick DTL attack) reminds me of Kvitova 2011 rather than Kerber 2012.

Kvitova
2009 Hobert W
2011 Brisbane W
2011 Paris[Indoor] W

Barthel
20112012 Hobert W
2013 Hobert RU
2013 Paris[Indoor] W

Of cource, I know Mona has to improve in many aspects and is unlikely to do such a big jump.
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Old Feb 4th, 2013, 11:34 PM   #25
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Re: Barthel 2013 = Kerber 2012

Barthel 2013 ≠ Kerber 2013
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Old Feb 4th, 2013, 11:46 PM   #26
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Re: Barthel 2013 = Kerber 2012

Quote:
Originally Posted by LenaDMania0003 View Post
Barthel's game (smooth big hitting, quick DTL attack) reminds me of Kvitova 2011 rather than Kerber 2012.

Kvitova
2009 Hobert W
2011 Brisbane W
2011 Paris[Indoor] W

Barthel
20112012 Hobert W
2013 Hobert RU
2013 Paris[Indoor] W

Of cource, I know Mona has to improve in many aspects and is unlikely to do such a big jump.
Barthel = Wimbledon Champ 2013.

Anyway, I think Mona will have some very good results this year, but to say she's going to do as well as Kerber did in 2012 is a big ask.
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Old Feb 5th, 2013, 01:25 AM   #27
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Re: Barthel 2013 = Kerber 2012

Quote:
Originally Posted by alex.2812 View Post
She was injured for half of the season last year, wasn't she?
she had a foot injury going into RG which really messed with her momentum/confidence.
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Old Feb 5th, 2013, 02:37 AM   #28
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Re: Barthel 2013 = Kerber 2012

Quote:
Originally Posted by Viktymise View Post
Barthel = Wimbledon Champ 2013.

Anyway, I think Mona will have some very good results this year, but to say she's going to do as well as Kerber did in 2012 is a big ask.
That is bold! Hey, I wouldn't complain if it happened. But unlike last year when she started off the same way, she has to maintain the momentum throughout the whole year.
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Old Feb 12th, 2013, 08:54 PM   #29
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Re: Barthel 2013 = Kerber 2012

Kerber 2012 - defeated top 15 Lisicki in all German Doha 1R

Barthel 2013 - defeated top 15 Kerber in all German Doha 1R

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Old Feb 12th, 2013, 10:09 PM   #30
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Re: Barthel 2013 = Kerber 2012

It's definitely too early. I don't believe for her good game all year long. She is still too inconsistent.
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