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View Poll Results: ?

1. 40 26.85%
9. 99 66.44%
Others.(Please specify.) 2 1.34%
Hard to say. 8 5.37%
Voters: 149. You may not vote on this poll

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Old Oct 10th, 2012, 02:04 AM   #16
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Re: 6÷2(2+1)=?

Quote:
Originally Posted by Inger67 View Post
No, because you do whatever is in the parenthesis first. So you Add 2 and 1 to get 3.

Then it's 6÷2(3)
so,what would you do if you have this 6 (Y+1) = ?
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Old Oct 10th, 2012, 02:10 AM   #17
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Re: 6÷2(2+1)=?

Quote:
Originally Posted by Rui. View Post
so,what would you do if you have this 6 (Y+1) = ?
That's different. You skipped out of the division aspect of the problem, that's what makes this unique.

6 / 2 (1 + 2) is really
6 / 2 x (1 + 2)

If the problem you said was 6/2 (Y + 1) = ...

You would get 3Y + 3 = ...
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Old Oct 10th, 2012, 02:11 AM   #18
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Re: 6÷2(2+1)=?

I don't want to sound like a smartass, but if you can't solve this.... there's probably something REALLY wrong with you
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Old Oct 10th, 2012, 02:11 AM   #19
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Re: 6÷2(2+1)=?

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Originally Posted by Rui. View Post
so,what would you do if you have this 6 (Y+1) = ?
= 6Y + 6
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Old Oct 10th, 2012, 02:12 AM   #20
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Re: 6÷2(2+1)=?

Quote:
Originally Posted by Inger67 View Post
That's different. You skipped out of the division aspect of the problem, that's what makes this unique.

6 / 2 (1 + 2) is really
6 / 2 x (1 + 2)

If the problem you said was 6/2 (Y + 1) = ...

You would get 3Y + 3 = ...
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Old Oct 10th, 2012, 02:13 AM   #21
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Re: 6÷2(2+1)=?

I can't believe 1 is winning this right now
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Old Oct 10th, 2012, 02:19 AM   #22
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Re: 6÷2(2+1)=?

Quote:
Originally Posted by Inger67 View Post
That's different. You skipped out of the division aspect of the problem, that's what makes this unique.

6 / 2 (1 + 2) is really
6 / 2 x (1 + 2)

If the problem you said was 6/2 (Y + 1) = ...

You would get 3Y + 3 = ...
I guess you're correct Then again, I'm still not sure. I just meant to say that you could play with what's inside the parentheses and then division and multiplication should be interchangeable but i'm not sure anymore.
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Old Oct 10th, 2012, 02:34 AM   #23
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Re: 6÷2(2+1)=?

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Originally Posted by New_balls_please View Post
I don't want to sound like a smartass, but if you can't solve this.... there's probably something REALLY wrong with you
I know, right? Even I solved it.
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Old Oct 10th, 2012, 02:41 AM   #24
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Re: 6÷2(2+1)=?

Quote:
Originally Posted by Inger67 View Post
That's different. You skipped out of the division aspect of the problem, that's what makes this unique.

6 / 2 (1 + 2) is really
6 / 2 x (1 + 2)

If the problem you said was 6/2 (Y + 1) = ...

You would get 3Y + 3 = ...
You have to distribute the 3 into the parenthesis first before you divide, no?
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Old Oct 10th, 2012, 02:51 AM   #25
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Re: 6÷2(2+1)=?

Right. Just because it would be 2(3) doesn't mean make it a parentheses rule.
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Old Oct 10th, 2012, 02:51 AM   #26
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Re: 6÷2(2+1)=?

Quote:
Originally Posted by Dav. View Post
You have to distribute the 3 into the parenthesis first before you divide, no?
If the problem was like this what would you do?

6/2 x (3)

By using Please Excuse My Dear Aunt Sally, which states Multiplication AND Division, you do whatever comes first from left to right. You divide first and then multiply.
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Old Oct 10th, 2012, 02:52 AM   #27
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Re: 6÷2(2+1)=?

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Originally Posted by In The Zone View Post
Right. Just because it would be 2(3) doesn't mean make it a parentheses rule.
Exactly, you distribute INSIDE the parenthesis not if it's outside like that. That's multiplication.
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Old Oct 10th, 2012, 02:54 AM   #28
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Re: 6÷2(2+1)=?

this is like doing 6*(1/2)*(2+1) It's 3 multiplications..
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Old Oct 10th, 2012, 02:54 AM   #29
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Re: 6÷2(2+1)=?

Quote:
Originally Posted by Inger67 View Post
If the problem was like this what would you do?

6/2 x (3)

By using Please Excuse My Dear Aunt Sally, which states Multiplication AND Division, you do whatever comes first from left to right. You divide first and then multiply.
Exactly.
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Old Oct 10th, 2012, 02:55 AM   #30
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Re: 6÷2(2+1)=?

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Originally Posted by delicatecutter View Post
I know, right? Even I solved it.
Wally

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