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Oct 10th, 2012, 01:04 AM   #16
Rui.
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Re: 6÷2（2+1）=？

Quote:
 Originally Posted by Inger67 No, because you do whatever is in the parenthesis first. So you Add 2 and 1 to get 3. Then it's 6÷2（3）
so,what would you do if you have this 6 (Y+1) = ?
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Oct 10th, 2012, 01:10 AM   #17
Inger67
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Re: 6÷2（2+1）=？

Quote:
 Originally Posted by Rui. so,what would you do if you have this 6 (Y+1) = ?
That's different. You skipped out of the division aspect of the problem, that's what makes this unique.

6 / 2 (1 + 2) is really
6 / 2 x (1 + 2)

If the problem you said was 6/2 (Y + 1) = ...

You would get 3Y + 3 = ...
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 Oct 10th, 2012, 01:11 AM #18 New_balls_please Senior Member     Join Date: Feb 2004 Location: Ann Arbor, MI Posts: 19,877 Re: 6÷2（2+1）=？ I don't want to sound like a smartass, but if you can't solve this.... there's probably something REALLY wrong with you __________________ PARRA SANTONJA ~ MATTEK-SANDS ~ MUGURUZA ~ RUS ~ V.WILLIAMS ~ GIORGI ~ BADOSA
Oct 10th, 2012, 01:11 AM   #19
The 2nd Law
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Re: 6÷2（2+1）=？

Quote:
 Originally Posted by Rui. so,what would you do if you have this 6 (Y+1) = ?
= 6Y + 6
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Oct 10th, 2012, 01:12 AM   #20
The 2nd Law
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Re: 6÷2（2+1）=？

Quote:
 Originally Posted by Inger67 That's different. You skipped out of the division aspect of the problem, that's what makes this unique. 6 / 2 (1 + 2) is really 6 / 2 x (1 + 2) If the problem you said was 6/2 (Y + 1) = ... You would get 3Y + 3 = ...
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 Oct 10th, 2012, 01:13 AM #21 Inger67 Senior Member     Join Date: Sep 2008 Posts: 30,487 Re: 6÷2（2+1）=？ I can't believe 1 is winning this right now __________________ Venus Williams • Urszula Radwanska • Garbiñe Muguruza • Simona Halep • Agnieszka Radwanska • Kristina Mladenovic • Taylor Townsend • Ajla Tomljanovic • Eugenie Bouchard • Carla Suárez Navarro TT Singles Current Ranking: #44 (CH Ranking: #11) Titles: Quebec City 2012, Cincinnati 2011 TT Doubles Current Ranking: #10 (CH Ranking: #8) Titles: Tokyo 2012 (w/New_balls_please), Stanford 2012, Carlsbad 2011, Osaka 2011 (w/rvugt) French Open 2013 Finalist (w/New_balls_please)
Oct 10th, 2012, 01:19 AM   #22
Rui.
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Re: 6÷2（2+1）=？

Quote:
 Originally Posted by Inger67 That's different. You skipped out of the division aspect of the problem, that's what makes this unique. 6 / 2 (1 + 2) is really 6 / 2 x (1 + 2) If the problem you said was 6/2 (Y + 1) = ... You would get 3Y + 3 = ...
I guess you're correct Then again, I'm still not sure. I just meant to say that you could play with what's inside the parentheses and then division and multiplication should be interchangeable but i'm not sure anymore.
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Oct 10th, 2012, 01:34 AM   #23
delicatecutter
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Re: 6÷2（2+1）=？

Quote:
 Originally Posted by New_balls_please I don't want to sound like a smartass, but if you can't solve this.... there's probably something REALLY wrong with you
I know, right? Even I solved it.
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Oct 10th, 2012, 01:41 AM   #24
Dav.
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Re: 6÷2（2+1）=？

Quote:
 Originally Posted by Inger67 That's different. You skipped out of the division aspect of the problem, that's what makes this unique. 6 / 2 (1 + 2) is really 6 / 2 x (1 + 2) If the problem you said was 6/2 (Y + 1) = ... You would get 3Y + 3 = ...
You have to distribute the 3 into the parenthesis first before you divide, no?
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 Oct 10th, 2012, 01:51 AM #25 In The Zone it's serena, bitch.     Join Date: Feb 2006 Posts: 23,869 Re: 6÷2（2+1）=？ Right. Just because it would be 2(3) doesn't mean make it a parentheses rule.
Oct 10th, 2012, 01:51 AM   #26
Inger67
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Re: 6÷2（2+1）=？

Quote:
 Originally Posted by Dav. You have to distribute the 3 into the parenthesis first before you divide, no?
If the problem was like this what would you do?

6/2 x (3)

By using Please Excuse My Dear Aunt Sally, which states Multiplication AND Division, you do whatever comes first from left to right. You divide first and then multiply.
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Oct 10th, 2012, 01:52 AM   #27
Inger67
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Re: 6÷2（2+1）=？

Quote:
 Originally Posted by In The Zone Right. Just because it would be 2(3) doesn't mean make it a parentheses rule.
Exactly, you distribute INSIDE the parenthesis not if it's outside like that. That's multiplication.
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Oct 10th, 2012, 01:54 AM   #28
slamchamp
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Re: 6÷2（2+1）=？

this is like doing 6*(1/2)*(2+1) It's 3 multiplications..
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Oct 10th, 2012, 01:54 AM   #29
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Re: 6÷2（2+1）=？

Quote:
 Originally Posted by Inger67 If the problem was like this what would you do? 6/2 x (3) By using Please Excuse My Dear Aunt Sally, which states Multiplication AND Division, you do whatever comes first from left to right. You divide first and then multiply.
Exactly.
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Oct 10th, 2012, 01:55 AM   #30
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Re: 6÷2（2+1）=？

Quote:
 Originally Posted by delicatecutter I know, right? Even I solved it.
Wally

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