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Old Aug 16th, 2013, 12:43 PM   #3279
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Re: Romania's Finest, Raluca Olaru!

Craiova Doubles

First Round : Olaru / Bogdan (N°1) w Juhaskova / Smitkova 6-2;6-2
Q/F : Olaru / Bogdan w Kucova / Njiric 6-1, 6-4
1/2 F : Olaru / Bogdan L Buzean / Shakovets (N°4) : 6-3,6-4
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