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View Full Version : Bogota: Yvonne Meusburger d. Jill Craybas 64 64


Xian
Feb 20th, 2008, 08:40 AM
:eek::eek: WTf HoW cAN MoOSE wIn A MAtCh AgAInsT an AMeRIcAN GuuRL????

REtiRE nOOOW JiLl C!!!!!

well done Yvonne :worship::worship: considering Jill was in great form recently :bounce::bounce:

LegionArgentina
Feb 20th, 2008, 09:16 AM
:eek::eek: WTf HoW cAN MoOSE wIn A MAtCh AgAInsT an AMeRIcAN GuuRL????

REtiRE nOOOW JiLl C!!!!!

:haha:
Xian vs cleo :boxing:

Congrats Yvonne :yeah:

shrOOf
Feb 20th, 2008, 12:15 PM
Jill :sad: Moonballed you to death :o

Hashim.
Feb 20th, 2008, 12:17 PM
:tape:

Jill:o

Yvonne :yeah:

gumoll
Feb 20th, 2008, 12:43 PM
I feel a Muller - Meusburger final :tape:

ElusiveChanteuse
Feb 20th, 2008, 12:45 PM
I feel a Muller - Meusburger final :tape:

You should tell me this for the Race game.:p

Jill :mad: :o

Ballbasher
Feb 20th, 2008, 12:52 PM
Yvi :)

TheBoiledEgg
Feb 20th, 2008, 12:54 PM
never in doubt on red clay

muller vs meusburger final would be death of tennis

Ellery
Feb 20th, 2008, 01:20 PM
Congrats Yvonne :D
Jill :hug:

Highlandman
Feb 20th, 2008, 01:39 PM
Expected on clay :p

Elwin.
Feb 20th, 2008, 02:10 PM
Jill :o

Renalicious
Feb 20th, 2008, 02:20 PM
So expected...

Nervenbuendel
Feb 20th, 2008, 02:44 PM
Ivy got a thousand volts of power and will blew all the haters away. :D :cool:

matty
Feb 20th, 2008, 02:47 PM
:eek::eek: WTf HoW cAN MoOSE wIn A MAtCh AgAInsT an AMeRIcAN GuuRL????

REtiRE nOOOW JiLl C!!!!!

well done Yvonne :worship::worship: considering Jill was in great form recently :bounce::bounce:

Why should she retire? She's already earned $50,000 this season. She's earned a million and a half since she turned pro. She's been in the top 100 for the last seven years! I'm sure a lot of people would like her "job". What have you ever done?

cheo23
Feb 20th, 2008, 03:33 PM
It's ONLY on CLay and don't Get ToO EXCITED!!!!!!!! :rolleyes: Jill Has done MORE than what Yvonne COuld possibly Achieve!!!!!

CooCooCachoo
Feb 20th, 2008, 03:39 PM
:sad: Jill :hug:

But it's not her surface.