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View Full Version : What's the Minumum Kim has to do vs. Dementieva?


-jenks-
Nov 10th, 2006, 08:58 PM
to make the semifinals?

jazar
Nov 10th, 2006, 09:08 PM
win the huge total of 4 games i believe

densuprun
Nov 10th, 2006, 09:08 PM
Yes, 4 games is enough.

azmad_88
Nov 10th, 2006, 09:09 PM
3 more now

-jenks-
Nov 10th, 2006, 09:10 PM
2 more now! ;)

muniu
Nov 10th, 2006, 09:16 PM
1 more now:)

Paul.
Nov 10th, 2006, 09:19 PM
do you think that she will be really happy after she wins her 4th game and the crowd will applaud really loudly?

or do you think that the crowd and even kim are far too confused by the system :lol:!!

i still dont get how momo is top of the yellow group when justine has a much better record in both sets and games. is it because momo beat justine? :confused:

miffedmax
Nov 10th, 2006, 09:19 PM
The way Lena's playing?

Show up.

twight6
Nov 10th, 2006, 09:21 PM
do you think that she will be really happy after she wins her 4th game and the crowd will applaud really loudly?

or do you think that the crowd and even kim are far too confused by the system :lol:!!

i still dont get how momo is top of the yellow group when justine has a much better record in both sets and games. is it because momo beat justine? :confused:

yes :)

If 2 players tie, then whichever player won in the RR advances
If 3 players tie, then set won percentage is used because H2H cannot be.

darrinbaker00
Nov 10th, 2006, 09:24 PM
The way Lena's playing?

Show up.
Richard Krajicek sure has earned his keep, hasn't he? ;)

Dexter
Nov 10th, 2006, 09:28 PM
here she comes...

Wannabeknowitall
Nov 10th, 2006, 09:28 PM
Stand on the court and let Dementieva serve.

muniu
Nov 10th, 2006, 09:29 PM
KIM IN SF :woohoo: :aparty:

Paul.
Nov 10th, 2006, 09:29 PM
yes :)

If 2 players tie, then whichever player won in the RR advances
If 3 players tie, then set won percentage is used because H2H cannot be.

oh right! thanks ;)