My 2004 WTA Champs Statistics

There have been lots of debates about the 2004 Season-ending Championships, so I was curious to see what the statistics are for the tournmament. I made the stats on averages of matches played. I then gave points out to determine who played the best, on average. Just read and enjoy.

1st Serve %

Maria Sharapova leads with 67.2% (8 pts.)
Amelie Mauresmo with 61.8% (7 pts.)
Svetlana Kuznetsova with 59.7% (6 pts.)
Lindsay Davenport with 57.7% (5 pts.)
Anastasia Myskina with 57.5% (4 pts.)
Elena Dementieva with 55.7% (3 pts.)
Serena Williams with 54.4% (2 pts.)
Vera Zvonareva with 53.7% (1 pt.)

Aces

Serena Williams leads with 8.4 (8 pts.)
Lindsay Davenport with 7 (7 pts.)
Amelie Mauresmo with 6.8 (6 pts.)
Maria Sharapova with 3.4 (5 pts.)
Svetlana Kuznetsova with 2.3 (4 pts.)
Vera Zvonareva with 2.3 (3 pts.)
Anastasia Myskina with 2 (2 pts.)
Elena Dementieva with 0.7 (1 pt.)

Double Faults

Serena Williams leads with 0.8 (8 pts.)
Svetlana Kuznetsova with 1.7 (7 pts.)
Lindsay Davenport with 3 (6 pts.)
Anastasia Myskina with 3.5 (5 pts.)
Maria Sharapova with 4.8 (4 pts.)
Vera Zvonareva with 5.7 (3 pts.)
Amelie Mauresmo with 6.3 (2 pts.)
Elena Dementieva with 9 (1 pt.)

Winning % on 1st Serves

Amelie Mauresmo leads with 77.8% (8 pts.)
Lindsay Davenport with 74.3% (7 pts.)
Serena Williams with 68.4% (6 pts.)
Maria Sharapova with 65.8% (5 pts.)
Anastasia Myskina with 62.8% (4 pts.)
Svetlana Kuznetsova with 62.3% (3 pts.)
Elena Dementieva with 54.3% (2 pts.)
Vera Zvonareva with 53% (1 pt.)

Winning % on 2nd Serves

Amelie Mauresmo leads with 49.3% (8 pts.)
Anastasia Myskina with 48.8% (7 pts.)
Lindsay Davenport with 48% (6 pts.)
Serena Williams with 47.4% (5 pts.)
Maria Sharapova with 42.8% (4 pts.)
Svetlana Kuznetsova with 39% (3 pts.)
Vera Zvonareva with 36.3% (2 pts.)
Elena Dementieva with 33% (1 pt.)

Winners

Maria Sharapova leads with 33.4 (8 pts.)
Serena Williams with 33 (7 pts.)
Lindsay Davenport with 26 (6 pts.)
Amelie Mauresmo with 22.5 (5 pts.)
Svetlana Kuznetsova with 20.7 (4 pts.)
Anastasia Myskina with 18 (3 pts.)
Elena Dementieva with 15.3 (2 pts.)
Vera Zvonareva with 11.3 (1 pt.)

Unforced Errors

Vera Zvonareva leads with 17.7 (8 pts.)
Amelie Mauresmo with 18.5 (7 pts.)
Lindsay Davenport with 21.3 (6 pts.)
Svetlana Kuznetsova with 21.3 (5 pts.)
Anastasia Myskina with 25.3 (4 pts.)
Elena Dementieva with 25.7 (3 pts.)
Maria Sharapova with 29.6 (2 pts.)
Serena Williams with 38.6 (1 pt.)

Break Point Conversions

Maria Sharapova leads with 64.4% (8 pts.)
Anastasia Myskina with 47% (7 pts.)
Elena Dementieva with 45.7% (6 pts.)
Serena Williams with 44.4% (5 pts.)
Lindsay Davenport with 43.3% (4 pts.)
Amelie Mauresmo with 43.3% (3 pts.)
Svetlana Kuznetsova with 37.7% (2 pts.)
Vera Zvonareva with 20% (1 pt.)

Net Approaches Won

Svetlana Kuznetsova leads with 79.3% (8 pts.)
Lindsay Davenport with 76.7% (7 pts.)
Maria Sharapova with 74.4% (6 pts.)
Serena Williams with 70.2% (5 pts.)
Amelie Mauresmo with 70% (4 pts.)
Elena Dementieva with 69.3% (3 pts.)
Anastasia Myskina with 62.3% (2 pts.)
Vera Zvonareva with 54.7% (1 pt.)

Points Won

Serena Williams leads with 92 (8 pts.)
Anastasia Myskina with 84.5 (7 pts.)
Amelie Mauresmo with 82 (6 pts.)
Maria Sharapova with 80.6 (5 pts.)
Lindsay Davenport with 79.7 (4 pts.)
Elena Dementieva with 60.3 (3 pts.)
Vera Zvonareva with 54.3 (2 pts.)
Svetlana Kuznetsova with 53.7 (1 pt.)

Here is the tally of points to determine who played the best, overall.

Lindsay Davenport with 58 pts.
Amelie Mauresmo with 56 pts.
Serena Williams with 55 pts.
Maria Sharapova with 55 pts.
Anastasia Myskina with 45 pts.
Svetlana Kuznetsova with 43 pts.
Elena Dementieva with 25 pts.
Vera Zvonareva with 23 pts.

There are a couple things to take from this point tally: #1) Obviously, Lindsay, Amelie, Serena, and Maria outplayed Anastasia, Svetlana, Elena, and Vera. #2) Elena and Vera do not deserve to be pronounced in the same sentence as anybody else in the 2004 WTA Tour Championships. They're not in the same league as the others.

I don't think you should give Vera 8 points for most unforced errors:p

Why does Serena get 8 points for having the most double faults? She should get the lowest amount of points, same with the UE collum

Why does Serena get 8 points for having the most double faults? She should get the lowest amount of points, same with the UE collum

Look at the numbes; I'm sure it'll click eventually ;)

Double Faults and Unforced Errors are calculated through least-most. Serena has 8 points in the Double Faults category because she had the least Double Faults.

:help: at my retardness...thought it said 8 not 0.8

:retard: