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View Full Version : Post Hingis...all the #1's have been getting tough draws!


for-sure
Jan 21st, 2004, 10:30 PM
It could not get any harder for Justine drawing Davenport and then Amelie. Or for Serena drawing Amelie and Justine at the French. And at the open Kim the current No.1 had Amelie, Davenport and then J-H-H.

I remember Hingis staying on top with a number of SF's/F thanks to (let's be honest) somewhat easy draws.

Post Hingis however, the No.1's have been getting killed by killer draws.

bandabou
Jan 21st, 2004, 10:41 PM
Yeah....specially during Serena´s reign...as soon as SOMEBODY beat her, that person would ALWAYS end up in her draw....Jennifer, Justine, Kim, Amelie...only Chanda didn´t keep the rule.

VS Fan
Jan 21st, 2004, 11:03 PM
This seemed to be true for Venus also. At Wimbledon 2003, everyone who had beaten Venus in the last six months was on her side and Everyone who had beaten Serena recently or ever was on her side.

However the plan just didn't work... they STILL played in the finals.

Well... Maybe it was just the luck of the draw, but it seems to happen quite often.

V&SGotItGoingOn
Jan 21st, 2004, 11:12 PM
The only thing that could have been worse for Justine, would have been if Venus would have been on her side instead of Amelie, that way she would probably play Venus for sure, then maybe Kim. OR if Venus stayed the number 11 seed and Justine drew her in the fourth round (not sure if that is possible) and then she would have either lindsay or amelie in the semis and kim in the finals... all in all though, pretty tough draw for Justine.

Sam L
Jan 21st, 2004, 11:13 PM
Um.. Hingis didn't have easy draws. She beat everyone relatively easily and the only players that troubled her were the Williams and Davenport and they were always ranked high enough so it seemed like she never faced trouble til the semis or finals. :shrug:

for-sure
Jan 21st, 2004, 11:40 PM
true Sam L. Sometimes when a player breezes through draws...it makes them look much easier

TonyP
Jan 22nd, 2004, 01:07 AM
Right. We can all remember that cake walk she faced at the AO in 2001, facing Serena, then Venus and then Jennifer in a row.

Or the '99 USO when she faced Venusin the semis and then Serena in the final or the...
oh, heck, you get the idea.

tennischick
Jan 22nd, 2004, 01:33 AM
TonyP...:worship:

for-sure
Jan 22nd, 2004, 01:45 AM
Although you are right tonyp. you have to remember that Venus and Serena were not back then. (99') what they are now.

bandabou
Jan 22nd, 2004, 01:46 AM
Right. We can all remember that cake walk she faced at the AO in 2001, facing Serena, then Venus and then Jennifer in a row.

Or the '99 USO when she faced Venusin the semis and then Serena in the final or the...
oh, heck, you get the idea.

Thing is that by ´01 Martina was no.1 in number/name only....

irinska
Jan 22nd, 2004, 05:44 AM
This AO is the weakest I've seen for years for the top players we all know the final 4 . Let's face the facts and not write such stupid things, easy draw for Hingis, nonesense .

anthonyqld
Jan 22nd, 2004, 05:48 AM
Henon-Hardenne will not meet Davenport as Davenport will lose to Vera who will then beat Double-H

GoGoMaggie
Jan 22nd, 2004, 05:50 AM
Plz stop making overgeneralzations or I would call you paranoid!

TonyP
Jan 22nd, 2004, 02:00 PM
Right again, Venus hadn't won Wimbledon and the USO open when she met Hingis at the AO semis in 2001 and lost 6-1, 6-1 to her.

Yes, players do through peaks and valleys.

Hingis wasn't the player she used to be by the end of 2001 or after Indian Wells in 2002, either. She was no longer at the top of her own game, and that is irrespective of any other player out there.

But that concept seems to be hard for some to grasp.

And as for Hingis staying on top with SFs and Finals, the last year she finished as number one was 2000 I believe. She WON nine tournaments that year, including Miami, Zurich and the Chase Championships. In fact, she won 20 more matches that year than anyone on the tour and more tournaments than anyone on the tour. She did not stay on top just by getting to finals.