Just in an introductory physics class and having trouble working this out...
A stone is dropped from the roof of a building; 1.30
after that, a second stone is thrown straight down with an initial speed of 18.0
, and the two stones land at the same time.
I have to figure out:
How long did it take the first stone to reach the ground?
How high is the building?
What are the speeds of the two stones just before they hit the ground?
I attempted using the formula x = x(0) + v(0)t + (1/2)at^2
and got 0 = x(0) + 0 + (1/2)(-9.8)(t^2)
and 0 = x(0) + 18t + (1/2)(-9.8)(t-1.3)^2
and worked that out to t = 1.6 seconds
unfortunately that was wrong, lol
any help?