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post #1 of 8 (permalink) Old Jan 28th, 2010, 05:31 PM Thread Starter
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Thumbs up Is the 33-5 & 28-3 Belgian stat truely unique or do ..

...we have similar serial multi tournament winnings around a slam ?

Now standings are 33-5 for the Australian tour of which 3 losses are against another Belgian...

Henin is 10-1 now loss against Clijsters in Brisbane
Wickmayer ended at 11-1 loss against Henin at AO
Flipkens is 5-2 lost against Bondarenko in Hobart and Henin at AO
Clijsters ended 7-1 terrible loss against Petrova

Without Flipkens the stat is 28-3 with only one loss against a non-Belgian (Petrova)

If Henin is to win on Sunday, the Belgians will have taken home the Auckland, Brisbane and the AO victory cup
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post #2 of 8 (permalink) Old Jan 28th, 2010, 05:33 PM
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Re: Is the 33-5 & 28-3 Belgian stat truely unique or do ..

Who cares, take it to the Belgian Forum.


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post #3 of 8 (permalink) Old Jan 28th, 2010, 05:51 PM
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Re: Is the 33-5 & 28-3 Belgian stat truely unique or do ..

This type of bad draw could continue this year, they still aren't ranked 1,2,3 in the world.
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post #4 of 8 (permalink) Old Jan 28th, 2010, 07:27 PM
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Re: Is the 33-5 & 28-3 Belgian stat truely unique or do ..

So the Belgians are doing almost as well this year as Dementieva was at this time last year by herownself.

Congratulations.

Max
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post #5 of 8 (permalink) Old Jan 28th, 2010, 08:37 PM
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Re: Is the 33-5 & 28-3 Belgian stat truely unique or do ..

To end this discussion with(out) a bang....






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post #6 of 8 (permalink) Old Jan 28th, 2010, 08:41 PM
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Re: Is the 33-5 & 28-3 Belgian stat truely unique or do ..

Quote:
Originally Posted by belzebub View Post
...we have similar serial multi tournament winnings around a slam ?

Now standings are 33-5 for the Australian tour of which 3 losses are against another Belgian...

Henin is 10-1 now loss against Clijsters in Brisbane
Wickmayer ended at 11-1 loss against Henin at AO
Flipkens is 5-2 lost against Bondarenko in Hobart and Henin at AO
Clijsters ended 7-1 terrible loss against Petrova

Without Flipkens the stat is 28-3 with only one loss against a non-Belgian (Petrova)

If Henin is to win on Sunday, the Belgians will have taken home the Auckland, Brisbane and the AO victory cup
Your message board name is extremely apt.
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post #7 of 8 (permalink) Old Jan 28th, 2010, 10:58 PM
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Re: Is the 33-5 & 28-3 Belgian stat truely unique or do ..

that's very good for belgium.

Ágnes Szávay
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Beijing, 2007, def. Jelena Jankovic 6-7(7) 7-5 6-2; Budapest, 2009, def. Patty Schnyder 2-6 6-4 6-2; Budapest, 2010, def. Patty Schnyder 6-2 6-4; Prague 2010, def. Zahlavova Strycova 6-2 1-6 6-2
Has wins over Schiavone, Radwanska, Hantuchova, Stosur, Petrova, Peng, Dementieva, Safina, Bartoli, Lisicki, Ivanovic, Pennetta, Azarenka, V. Williams.
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post #8 of 8 (permalink) Old Jan 29th, 2010, 08:02 AM
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Re: Is the 33-5 & 28-3 Belgian stat truely unique or do ..

Quote:
Originally Posted by Loudman View Post
This type of bad draw could continue this year, they still aren't ranked 1,2,3 in the world.
and yet they clearly SHOULD be!
This wta ranking system just sucks

^^^^ for all my ladies
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